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July 13, 2011 / Aiman Kiwan

PhotoMOS Input Circuits

PhotoMOS The latest electronic equipment is characterized by smaller size, greater functionality and better performance than ever before. If size is to be reduced and performance increased, power management of the electronic device is a serious issue. For these reasons semiconductor relays have become very popular when galvanically isolated switching of load circuits is required. Besides other advantages, semiconductor relays are smaller than electromechanical relays and  have a lower power consumption. Nevertheless there are some basic points one should pay attention to when using a PhotoMOS relay in an electrical circuit.

The input side of a PhotoMOS relay consists of a light emitting diode. If a current flows through the LED it starts emitting light. The light passes through a silicon resin, providing galvanic  isolation of input and output circuits, and is detected by an array of solar cells. This results in a voltage drop across the solar cells, which is used to drive MOSFETs switching the load circuit. High-function Economy types of PhotoMOS relays (e.g. AQV254) have a maximum LED operate current IFon of 3 mA (typical 0.9 mA) at an ambient temperature of 25°C. The LED’s forward voltage VF for 5 mA forward current is 1.14 V, hence RF can be calculated:

PhotoMOS Rf Calculation

This calculation is valid for a simple driving circuit like shown in Figure 1 below.

Figure 1: Simple PhotoMOS Driving Circuit

Figure 1: Simple PhotoMOS Driving Circuit


As already implied, temperature is a central issue when designing modern electronic circuits. Since the LED operate current increases as the temperature rises, a value IF of 5 mA at a maximum temperature 85°C should be supplied for safe operation.

The LED’s forward voltage depends on the forward current and the temperature. For the above values, it will decrease to approximately 1.03 V, as seen in Figure 2.

Figure 2: LED Forward Voltage vs. Ambient Temperature

Figure 2: LED Forward Voltage vs. Ambient Temperature

Hence the maximum value for RF can be calculated:

PhotoMOS Max Rf Value

Assuming a resistor with a 5% tolerance and a temperature coefficient of 250 ppm/K, we will choose the next lower value from standard resistors: RF = 680 Ω.

PhotoMos Lower Resistance Value Equation

Since RF’ is smaller than RF, the standard resistor of 680 Ω will ensure safe operation over the whole temperature range. If supply voltage contains ripple the lowest possible value of Vcc has to be used for calculation. Pay attention to the PhotoMOS relay’s highest possible value of the driving signal and maximum forward current.

Power consumption of PhotoMOS relays is much lower compared to electromechanical relays, nevertheless some logic circuits cannot sink or source much current. Driving a PhotoMOS relay with such logic circuits requires additional parts, e.g. bipolar transistors or CMOS gates. Newer CMOS gates can sink significantly more current than parts using older technologies.

An example for controlling a PhotoMOS relay with a transistor or a CMOS inverter is given in Figure 3.

Figure 3: PhotoMOS Driving Circuit

Figure 3: PhotoMOS Driving Circuit

This circuit requires more parts and an additional voltage supply. Care has to be taken when calculating the value of RF, since there is a voltage drop Von across the bipolar transistor (saturation voltage VCESat) or across the output of the CMOS inverter (LOW level output voltage VOL). Because of this voltage drop the voltage across the input resistor is lower and RF can be calculated:

PhotoMOS Rf CalculationBased on this result we can compare the maximum allowable resistor value RFmax with the worst case value RF’ of a 680 Ω resistor (5% tolerance, 250 ppm/K and 85°C ambient temperature). Since RF’ = 724.71 Ω is greater than RFmax a resistor value of 680 Ω is not sufficient to guarantee switching operation under all conditions. For this example one could choose a resistor value of 470 Ω, 560 Ω or a 680 Ω resistor with a higher tolerance class.

Reducing the value of RF causes higher currents to flow through the LED. Providing a higher LED current will lead to higher currents in the array of solar cells. Hence loading and unloading of the output MOSFET’s intrinsic capacitors will be done faster with a higher solar cell current, and faster switching times of the PhotoMOS relay can be realized (Figure 4, valid for AQV25_).

Figure 4: Turn On Time vs. LED Current for AQV25_

Figure 4: Turn On Time vs. LED Current for AQV25_

As stated above, higher LED currents lead to faster switching times. On the other hand, increasing the LED current of the PhotoMOS relay results in increased power dissipation. To compensate for this effect, provide a higher LED current for switching operation and reduce it afterwards to lower power dissipation. This can be done with a simple circuit as shown in Figure 5.

Figure 5: PhotoMOS Speed-up Circuit

Figure 5: PhotoMOS Speed-up Circuit

The capacitor has no voltage drop across it when the circuit is in an off-state. As soon as a control signal is applied, this results in a high inrush current, limited by the resistor RI, through the capacitor and the LED. After the capacitor C is charged, current no longer flows through it, so that the two resistors RI and RF determine the LED current. Based on the previous calculations the maximum value for RI + RF = 714 Ω.

The resistor RI determines the peak inrush current value, which shall be 20 mA for this example. The value VF for the LED forward voltage at 20 mA current and ambient temperature of 85°C can be taken from Figure 2.

PhotoMOS RI CalculationWe will choose a standard resistor value of 150 Ω for RI.

PhotoMOS RI as 150 ohmsThis yields a standard value of 560 Ω. Checking RFmax’ will result:

PhotoMOS 560 Ohm Yieldwhich is higher than RFmax. Therefore RF will be reduced to 470 Ω to ensure safe operation over the whole temperature range. The inrush current will decrease according to an e-function. To have any effect on the switching time of the relay, the following assumption can be made: time constant τ = RI · C shall be equal to two times the maximum turn on time τ = 2 · Ton.

PhotoMOS C ValueWe can choose a standard value C = 22 μF. Pay attention when using a bipolar transistor: its collector current must reach the desired current values for both peak and continuous state. To realize this, a sufficient base current must be supplied. Please note the DC current gain of your transistor and its tolerances when designing the base resistor for safe switching conditions.

Circuit simulation programs like PSpice are very useful for designing electrical circuits. By using computer aided design programs, influences of single parts and parameters can be easily determined. Please visit our internet online catalog to download the latest PSpice models for our PhotoMOS relays. After considering design rules, your circuit design can be verified with a simulation program and by an experimental set-up.

As previously seen, it is quite easy to control PhotoMOS relays if one pays attention to a few key points. This makes it easy for the user to make use of the advantages PhotoMOS relays offer over electromechanical relays:

  • Low Input Power Consumption
  • Small Size
  • High Switching Frequency
  • Higher Lifetime
  • Stable Contact Resistance Over Lifetime
  • No Switching Noise
  • No Contact Bounce
  • No Contact Arcs

2 Comments

Leave a Comment
  1. michael fox / Jan 10 2013 4:38 PM

    I’m trying to figure out how to do ESD protection on the input. I’m thinking that an external diode can be used to protect it in the reverse direction, but what to do about the forward direction?

    Looking at the datasheet for AQZ202, I model the input as a generic LED and simulate an 8kV HBM strike in the forward direction. Sure enough the peak current around 1.5A is well beyond the absolute maximum.

    The voltage across the terminals is limited by the LED Vf so a voltage-triggered protection device like a TVS diode won’t help.

    I looked into series overcurrent protection like a resetable PTC fuse, but they are too slow to stop an ESD event.

    Increasing input resistance is out because that’s how we set the current.

    An RC across the input terminals would almost work, but it would have the opposite effect of the RC peaking circuit recommended in this article, slowing the input rise time which slows the switching time. This seems like the best option, but still not great. Can you offer any advice?

    • Aiman Kiwan / Jan 14 2013 11:01 AM

      Hello Michael,
      We really appreciate your interest in our PhotoMOS relays and understand your application has a need to protect against ESD over voltage events.

      I agree that the most effective method is to employ a diode. In the case of human model ESD simulation, the amplitude can rise up to several thousand volt in nS durations. This happens in the forward direction of the LED. Please note that Vf of LED is a MINIMUM value that is required to maintain the forward biasing of diode. So this value can be exceeded as long as the input power does not exceed 75mW.

      An RC network is not an ideal solution for ESD. It is usually used to protect from slower types of transients, such as surge events that have a uS duration.

      Finally, Fuse or PTC will not protect against ESD as they are only effective to limit against overcurrent rather than overvoltage events.

      Regards,
      Aiman

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